a challenging question. please help me! [1]

question:
a remote pc is linux ,have a ip 192.168.1.2;
another a pc is linux, have a ip 192.168.1.209, have also a ip 10.71.144.80; the two pc that there are not video. a local pc is windows, have a ip 10.71.144.90. it was installed xManager 2.0. Now, I want to connect 192.168.1.2, how to do?

Program Ver. : Xmanager 2.x
Connection Method : XDMCP connection

Let's call:

Linux A: 192.168.1.2 Linux
Linux B: 192.168.1.209, 10.71.144.80 Linux
PC: 10.71.144.90 PC

just so it's easier to call them by names.

Solution 1. (This involves network reconfiguration)
From your description, I assume that you can connect to Linux B, but not A. This is usually because Linux A cannot reach your PC via TCP port 6000~6010. Talk to your network administrator to allow this backward connections to your PC.

Solution 2.
If you can SSH to Linux A, then you can launch its applications (including desktops) by using X11 Forwarding. Here is a thorough guide on how to launch individual application using SSH:

Running X application through SSH protocol: /products/xmg_tutorial6.html

Running KDE or Gnome through Secure Shell tunnel: /products/xmg_tutorial7.html


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